Breviarium - short Latin historiographical work written by Festus. Article “Breviarium (Festus)” in Latin Wikipedia has 24.9 points for quality (as of July 1, 2025). The article contains 1 references and 5 sections.
Since the creation of article “Breviarium (Festus)”, its content was written by 1 registered users of Latin Wikipedia and edited by 1 registered Wikipedia users in all languages.
Breviarium is on the 763rd place in local ranking of books on Latin Wikipedia in all the time.
The article is cited 13 times in Latin Wikipedia and cited 13 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Latin: #10083 06.2008 |
Global: #4005034 06.2008 |
| Best Rank | Latin: #8123 06.2008 |
Global: #1619003 06.2008 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Latin Wikipedia the most popular articles on that day were: Ecclesia Catholica Romana, Nova Caesarea, Collegium Regale (Cantabrigia), Iosephus Gabriel, Aloysius Schwartz, Lingua Latina, Mathematica, Varkaus, Liber chronicarum sive tribulationum ordinis Minorum, Civitates Foederatae Americae.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(6.87+5.88+0+35.71+75.96)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
